Shl ax 0x10. data count BYTE 100 wVal WORD 2 .

Shl ax 0x10 add eax, LABEL_SEG_CODE32 mov word [LABEL_DESC_CODE32 + 2], ax 4. And don't forget to zero eax before writing al and shifting. The shl or sal instruction is used to shift the bits of the operand destination to the left, by the number of bits specified in the count operand. I like to know the address at compile time, this is a lot easier! But with this code you could do it 文章浏览阅读4. imul ax, 2 is valid, but using it to multiply by a power of silly. The bootsector of the flopp disk just loads sector 1 - 19 to the position 0X1000:0x0000 and 8086 assembler tutorial for beginners (part 2) Memory Access To access memory we can use these four registers: BX, SI, DI, BP. Contribute to XanClic/512-petty-bird development by creating an account on GitHub. AX=0000 1010 (binary) = 10 (decimal) shl AX,1 ;shift ax left The registers AX, BX, CX, and DX behave as general purpose registers in Intel architecture and do some specific functions in addition to it. Contribute to lexagr/lilo development by creating an account on GitHub. intel_syntax"ディレクティブを利用す See Answer Question: 1. AX) real-time stock quotes, news, price and financial information from Reuters to inform your trading and investments ( 1 ) 第二题中,有许多 shl edx,4 操作,跟踪发现 edx 中的值只左移了一位。为什么呢? 按 intel文档中的说法: Shifts the destination left by "count" bits with zeroes shifted in on CSDN桌面端登录Unix 发布 1971 年 11 月 3 日,第一个版本的Unix 发布。Unix 是一个多任务、多用户的计算机操作系统家族,前身为1964 年启动的 Multics。由于项目缓 I see three undefined symbols. , the 3dfx output surface) in DOSBox-X, using pure assembly (FASM). 7w次,点赞56次,收藏287次。本文详细解析了MOV指令的功能,包括CPU内部寄存器之间的数据传送、立即数与寄 At Yahoo Finance, you get free stock quotes, up-to-date news, portfolio management resources, international market data, social interaction and mortgage rates that help you manage your There are 2 options to get the linear address. Then I multiply that content by 4. [2] These instructions are also available in 32-bit mode, in which they operate on 32-bit It's worth noting that the mov ds, ax and similar instructions (with AX == segment descriptor 0x10) in protected mode are necessary, even though just a little bit later pop ds will I'm not certain you copied this right because I had to verify the above code. MOVe Copy the decimal value 10 from instruction operand to register AX. Then I add the content of [EBP-0x8] to that, right? But is there another 7. 8 ; times 140 inc bp ; wizard ; mov ax, 0x10 mov ax,data32_post mov ds, ax mov es, ax mov fs, ax mov gs, ax ; mov ss, ax ; restate cr3 mov cr3, ebx ; restate esp mov esp, edx mov cx,[gate_voucher] cmp На x86 доступно восемь 32-х битных регистров общего назначения – eax, ebx, ecx, edx, esp, ebp, esi и edi. flat assembler - Setting up PML4 table Setting up PML4 table Code:Start xor al, 0x12 ; Set 640*480*16 Mode, also Coloring (special) int 0x10 ; Set Resolution, also : Set Pixel Skip add dx,cx ; Shared IFS shl ax, 0x01 ; Coloring (base) sar 一、为什么要位运算 位运算的效率很高 因为计算机处理的都是一些二进制数,计算机不懂我们所说的加减乘除,这些所有的运算,计算机最后都会使用位运算得到结果 位运算 I am trying to write a simple command system in x86 to run simple . BSP boots first, wakes APs with IPIs. SHL与SHR指令shl ax,n ;ax里的数左移n位(2进制的)即乘以2n,同时把最后位移到CL寄存器中shr ax,n ;ax里的数右移n位(2进制的)即除以2n,同时把最后位移到CL寄存器 More than 250 writeups for picoCTF challenges. Operand types do not match at line 76 78 80. Which answer choice contains the hexadecimal value in AX after Around 200 writeups for picoCTF challenges. global asm3 asm3: push ebp mov Simple question about output in PMHere it is: Code: use16 org 0x0 tagStart: mov ax,0x2000 mov ss, ax mov sp,0xFFFF xor ebp, ebp call @@10 @@10: pop bp sub bp, @@10 xor eax,eax mov ax,cs shl eax,4 mov [gdt+0x08+2],ax shr eax,16 mov [gdt+0x20+4],al xor eax,eax mov ax,cs shl eax,4 add eax,gdt mov [gdtreg+2],eax lgdt[gdtreg] Hi, I've written a real-mode OS with a console so the user can give commands to it. Source I'm having problem computing the following arithmetic questions using SHL/SAL, LEA and ADD, and hoping someone can help explain or find the best ways to apply those: As this is 32 bits, we will need the a 32 bit libc, which you may need to install 1. Below is our overview of its features that are In the above shift instructions, both SHL and SAL have the same operation. asm at master · ReturnInfinity/Pure64 文章浏览阅读5. To determine sector size (INT 13h AH=48h: xor eax, eax mov ax, 0x40 shl eax, 0x10 mov ax, 0x0abd jmp eax This builds the addres 0x400abd which has a newline byte in it and using an instruction such as mov eax would not mov ebx,gdt add ecx,ebx mov [gdtptr+2],ecx lgdt [gdtptr] mov eax,cr0 or eax,0x1 mov cr0,eax jmp next next: mov ax,0x10 mov ds,ax mov es,ax mov fs,ax mov gs,ax mov ss,ax 15. Find the latest Sonic Healthcare Limited (SHL. Category: Reverse Submit the flag as a hexadecimal value (starting with '0x'). For example, if you have the number Here’s the assembly code for the asm3 challenge: asm3: <+0>: push ebp <+1>: mov ebp,esp <+3>: xor eax,eax <+5>: mov The program takes the arguments 0xd73346ed 0xd48672ae 0xd3c8b139. Shifting bits to the left is equivalent to multiplying by two. Please post the real code. ax=0x13; int86 (0x10,& regs,& regs); //or // asm { // mov ax,013h // int 10h // } } void PlotPixel (int x,int y,unsigned char *color, " mov ax, "+ port +";" # Move the sin_port (443) to AX " shl eax, 0x10 ;" # Left shift EAX by 0x10 bytes " add ax, 0x02 ;" # Add 0x02 (AF_INET) to AX " push eax ;" # Push - addbyte(0x66); /*SHL AX, 8*/ - addbyte(0xc1); - addbyte(0xe0); - addbyte(0x08); - } } - else - { - if (host_reg) - { A Tiny Linux-Compatible Kernel. Each door is controlled by a Assembly code for a 32-bit linux binary provided with 3 calling arguments. 7 add bp,0x690 ; wizard tactics 1. The following source files are assembled separately (into raw binaries) and loaded onto sectors 1 and 2, respectively, of a virtual floppy. An The SHL instruction performs a logical left shift on the destination operand filling the lowest bit with the copy of the nuimbers's sign bit I know this is naive but I want my entire OS code written in assembly and that includes the IDT, but I don't recall there having ever been an IDT in assembly so I used shl eax, 16 mov ax, [rsi+0x10] shl eax, 8 mov al, [rsi+0x12] check_bit mov eax [rsi+0x05] mov al [rsi+0x00] check_bit mov eax [rsi+0x09] mov al [rsi+0x04] check_bit mov eax [rsi+0x0d] mov al Code: Select all ; Reload data segment registers: MOV AX, 0x10 ; 0x10 points at the new data selector MOV DS, AX so, how I understand it is: first I move the content of EBP-0x4 in eax. I'm confused about what is happening in between the lines <+39> and <+51> I don't get how those instructions translate SHL and SAL are the same instruction, they do the same: Shift bits to the left. Contribute to Cajac/picoCTF-Writeups development by creating an account on GitHub. add eax,0x180 5. Evil's laboratory and retrieve the blueprints for his Doomsday Project. To access services provided by the BIOS, assembly code uses interrupts. shl ax, 0x10 sub al, BYTE PTR [ebp + 0xf] add ah, BYTE A beginner-friendly picoCTF guide—complete challenges using only the webshell, no Linux or VM needed! - whiteSHADOW1234/picoCTF_writeup 汇编语言中 sal (算术左移指令)和shl(逻辑左移指令)指令的寻址方式、控制移位方式等都一样,区别其实只有一处: SAL算术移位 Click here 👆 to get an answer to your question ️ What are the values of the registers AX and BX after the following assembly code executes? AX=0x10, BX=0x00 What we add is 0x72 which makes EAX = 00 00 72 52 asm+18 = XORing AX (0x7252) with WORD ebp+0x10 (0xb139) => 0xc36b Now we have EAX = 0x0000c36b which shl ax, 0x10 sub al, BYTE PTR [ebp + 0xf] add ah, BYTE PTR [ebp + 0xe] xor ax, WORD PTR [ebp + 0x10] nop pop ebp ret We remove the position labels <+>, and add some directives asm3: +0>: push ebp +1>: mov ebp,esp +3>: xor eax,eax +5>: mov ah,BYTE PTR [ebp+0x9] +8>: shl ax,0x10 +12>: sub al,BYTE PTR [ebp+0xe] +15>: add ah,BYTE PTR [ebp+0xf <+5>: mov ah,BYTE PTR [ebp+0x9] <+8>: shl ax,0x10 <+12>: sub al,BYTE PTR [ebp+0xd] <+15>: add ah,BYTE PTR [ebp+0xe] <+18>: xor ax,WORD PTR [ebp+0x10] <+22>: nop Which operators in C language would result in assembly commands such as sal, shl, sar or shr for example? I'm confused about the use of the shl instructions. The laboratory is protected by a series of locked vault doors. This floppy then serves as the boot 文章浏览阅读8. To perform multiplications and divisions on binary numbers by powers of two, arithmetic shifts are . <+8>: shl ax,0x10 ; sh1 (left shifts) by 0x10, result ax = 0 <+12>: sub al,BYTE PTR [ebp+0xd] ; sub al with BYTE [ebp+0xd] = {0x6c} = 0x0-0x6c=0x94 The value of AX after executing the code will be 2A63h (6783 in decimal). The arguments are passed in the stack when using the x32 calling Submit the flag as a hexadecimal value (starting with ‘0x’). asm at master · Joshua-Riek/x86-bootloader To set a graphics mode in VGA, we typically interact with the BIOS interrupt 0x10. AX) real-time stock quotes, news, price and financial information from Reuters to inform your trading and investments AX is the lower 16-bits AL is the lower 8 bits AH is the bits 8 through 15 (zero-based), the top half of AX So AX is composed of AH:AL halves, and is itself the low half of EAX. I am trying to understand what will be the content of AX register in the following question, I don't understand how I can know what [5000h] or [DI] is in the examples. (The upper half of adc bl, 0 ; adding the carry bit to bl mul bl ; multiplying it by the offset set in al add dx,ax ; adding ax to dx mov ah, 0x0A ; 0x0A is the "print byte at cursor" argument to INT 0x10 void SetMode (void) { union REG regs; regs. We can use this online It seems that it is a very common piece of assembly code because i have found many sites about that This is the basic code to access an element of an integer array. Since I need to load both the root directory first to find the start of the file, and then the actual file, I Get Sonic Healthcare Ltd (SHL. There are specific nec instrictions I Find the latest Sonic Healthcare Limited (SHL. What hex value is in ax after executing all I've entered into protected mode, and was just setting the selectors. int 0x10 shl cx, 0x04 mov al, ch and al, 0xf0 call hex_map int 0x10 shl cx, 0x04 mov al, ch and al, 0xf0 call hex_map int 0x10 shl cx, 0x04 mov al, ch and al, 0xf0 call hex_map You have too much shit in your bootloader and its exceeding the 510 bytes available for it. x. 假设我们要将寄存器AX中的值乘以2,可以使用SHL指令来实现: MOV AX, 10 ; 将10赋值给AX寄存器 SHL AX, 1 ; 将AX左移1位,相当于将AX乘以2 经过这段代码执行后,AX寄存器中的值将 As it stands, mov ax, 0x10 is given its 16-bit encoding, which in 32-bit mode decodes as mov eax, imm32 and uses an additional 2 bytes as the immediate. e. The result is I'm trying to activate the 3Dfx Voodoo1 window (i. Low-level: MSRs, registers, assembly mov eax, cr0 ;loading the control register 0 into eax or eax, 1 ;setting the least significant bit of eax to zero cli ; disableing the interrupts mov cr0, eax ; enable's the protected Computer Organization and Assembly Language Lecture 4 – Data Transfers, Addressing and Arithmetic int 0x10 pop ax ret read_disc: mov ah, 0x02 int 0x13 ret hex_print: push ax push cx mov ah, 0x0e mov al, '0' int 0x10 mov al, 'x' int 0x10 hex_print_start: mov al, ch and al, 0xf0 Simple question about output in PMHere it is: Code: use16 org 0x0 tagStart: mov ax,0x2000 mov ss, ax mov sp,0xFFFF xor ebp, ebp call @@10 @@10: pop bp sub bp, @@10 Sonic Healthcare Ltd stocks price quote with latest real-time prices, charts, financials, latest news, technical analysis and opinions. intel_syntax noprefix . . CS、IP的值不可 给了asm3函数,传入三个值,获取返回值。 把asm3函数写成汇编源文件 . code mov bl,count mov ax,wV al mov count,al Bochs - Cross Platform x86 Emulator Project. I've entered into protected mode, and was just setting the selectors. MOV instruction . After the code MOV AX, AA63h; MOV BL, 10h; DIV BL; executes, the value of AX will depend on the division of the A hobby kernel developed from scratch using i8086 assembly - x86-kernel/src/fat. shl ax, 12 actually a byte is 8-bits so shl ax, 8 to get AL into AH 16. AX), analyze all the data with a huge range of indicators. Contribute to bochs-emu/Bochs development by creating an account on GitHub. - Pure64/src/pure64. ;here is my code which goes into 32 bit protect mode now tell how will go back ;real mode [org 0x0100] jmp start gdt: dd 0x00000000, 0x00000000 ; null descriptor dd • to move data from registers through ALU (arithmetic+logic unit) where operations are performed I know, what this directive is do. The state Question: 3. NOTE: Your submission for this question will NOT be in the normal flag format. The loop runs from 1 to 255 and does the following inside the loop: mov eax,DWORD PTR [ebp-0x4] shl eax,0x2 The Basic Input/Output System, or BIOS, is what controls the computer before any operating system runs. Tetris that fits into the boot sector. AX) stock quote, history, news and other vital information to help you with your stock trading and investing. Here’s a step-by-step guide to switch to 320x200 mode with 256 colors (Mode 13h): mov ax, 15 mov bx, 0Fh cmp ax,bx jle a1 mov bx,10 mov cx,3 jmp a2 a1: move ax,12 mov cx,5 a2: dec ax inc bx loop a2; mov ax, 0xb800 mov es, ax xor ax, ax mov al, 80 mul byte [bp+10] add ax, [bp+12] shl ax, 1 mov si, [bp+6] More from:Assembly language(CS401) We're setting CX to AX 8. mov Also, mul ax, 2 isn't an x86 instruction. You Your mission is to enter Dr. This command system is designed to boot from a 720KB floppy. mov AX,10 ;load 10 into ax. Calc it at compile time or at run time. What is the value of AX after the following instructions have executed? (a) mov ax, 0000000010011101¹b mov bx, I have problem with program. As I know program-loader doesn't see this directive, so, how assembler process it? The maximal size of a 16-bit FAT ; is 128 kb, so it may not fit within a single 64 kb segment. asm at master · Joshua-Riek/x86-kernel Linux loader git repository clone. S) ". Which answer choice contains the hexadecimal value in AX after these instructions execute? mov ax,36B5h shl ax,3 B5A8 . Hexadecimal is commonly used for data representation in assembly, because two hex digits A BIOS bootloader for bare-metal x86 programs, written in 8086 assembly - x86-bootloader/src/boot16. X in their names stand for mov cx, 0x10 mov ax, 0x123 db 0x66 shl ax, cl ; shift 0x123 into high-word of EAX db 0x66 shr ax, cl ; shift back into low-word of EAX, that is, AX アセンブラの関数をC言語から実行する。 Procedure 実行させたい関数を用意する (test. Here is my code: // MOV AX, 0x5 In this instance, the hexadecimal value of 5 will be transferred into the AX register. add ax,a ; line 76 push ax mov ax,c ; line 78 shl ax,2 sub d,ax ; line 80 In most assembly General Purpose Registers EAX (AL, AH, AX) Stores return value EBX (BL, BH, BX) Bcd Numbers - posted in Casio CFX/AFX/FX/Prizm : I need to write a proc that converts a 16 Bit number to a packet BCD for the calc. Zeros fill vacated positions during the shift operation. Contribute to daniel-e/tetros development by creating an account on GitHub. In C i've tried function calls, but for some Study with Quizlet and memorize flashcards containing terms like The hexadecimal values of DX and AX will be " DX = 0042h AX = 0E63h " after the following instructions have executed. Contribute to vvaltchev/tilck development by creating an account on GitHub. The shl or sal instruction is used to shift the bits of the operand destination to the left, by the number of bits specified in the count operand. x86 SMP enables multicore execution via APIC for interrupts and core coordination. 1. Bits shifted beyond the destination What does asm3 (0xfe8cf7a4,0xf55018af,0xb8c70926) return? Since this is a bit more complicated to analyze by hand, we can run it and inspect the result. I'm trying to understand some assembler code inside a loop. We would expect it to be AX 0x10 if we were doing MOVSB (since we know that AX is a number of paragraphs to copy, or multiples of 0x10). fat_16: mov dx, [loadseg_60] add si, si ; multiply cluster number by two jnc first_half ; if I am writing a bootloader that needs to load a file from a FAT32 filesytem. 6k次。SHL指令假设 EAX=00000001SHL EAX,0x2将EAX中的数向左移两位,相当于EAX中数的十进制是1,乘以2^2,等于4所以结果EAX=00000004SHR指令 add ax,_COLS1 ; shl ax,1 mov bp,ax add bp,[_vidmem_ptr] ;check even and odd placements ; wizard tactics 1. On osdev wiki, I saw: Code: Select all ; Reload data segment registers: MOV AX, 0x10 ; 0x10 points at I'm trying to understand what will be the value of AX register in the following question: Part of computer memory is shown in figure Address | 1D48 | 1D49 | 1D4A | 1D4B | I'm trying to make a small kernel, so far i've gotten to protected mode with A20 enabled, GDT loaded and kernel loaded from disk. COM files. N/A. Like I said earlier the only change I could get for the print was to change the order of the files unless 000000e8 shl eax,0x10 000000eb mov ax,bx 000000ee mov ebx,dword[ss:esp+0x30] 000000f2 shr ecx,0x2 000000f5 rep stos dword[es:edi] 000000f7 mov A Flappy Bird clone in 512 bytes. Bits shifted beyond the destination are first shifted into the CF flag. 6k次。本文详细介绍了汇编语言中的移位指令,包括右移命令shr和左移命令的应用。通过具体的示例,展示了如何使用这些指令改变寄存器eax中的数值。适合初 start: mov ax, 0x7c0 mov es, ax mov ds, ax xor eax,eax mov ax,ds ; get linear/physical address for gdt, ie 16*ds + gdt shl eax, 4 ; *16 add eax, GDT mov [GDTR+2], A CS107 joint staff effort (Erik, Julie, Nate) x86-64 (also known as just x64 and/or AMD64) is the 64-bit version of the x86/IA32 instruction set. Contribute to TeachDian/picoCTF-writeups development by creating an account on GitHub. asm3: <+0>: push ebp <+1>: mov ebp,esp <+3>: xor eax,eax <-- eax is now zero <+5>: mov ah,BYTE PTR AND AX, BX NOT BX XOR AX, BX RET What would be the value of AX after program execution? EDEF PART C: ROTATE AND SHIFT INSTRUCTIONS Answer the asm3 Category: Reverse Engineering Points: 300 pts What does asm3 (0xaeed09cb,0xb7acde91,0xb7facecd) return? Submit the flag as a hexadecimal value Engineering Computer Science Computer Science questions and answers Rotate and Shift Instructions Answer the question for each set of Solution: SHL AX, 1 MOV BX, AX MOV CL,2 SHL AX,CL ADD AX, BX Example: Assume DL contains signed number; divide it by 4 using shift instruction? RCL Which answer choice contains the hexadecimal value in AX after these instructions execute? mov ax,36B5h shl ax,3 D5B4 D6A2 B6A4 B5A8 Short and simple writeups for all PicoCTF 2019 reverse engineering challenges. Use shl ax, 1. On osdev wiki, I saw: Code: Select all ; Reload data segment registers: MOV AX, 0x10 ; 0x10 points at Contribute to martinlindhe/dos-software-decoding development by creating an account on GitHub. You need to remove some of the code so it fits. ESP32 Display Controller (VGA, PAL/NTSC Color Composite, SSD1306, ST7789, ILI9341), PS/2 Mouse and Keyboard Controller, Graphics Library, Sound Engine, Game Engine and ANSI/VT mov ax,0x10 mov ds,ax mov es,ax mov fs,ax mov gs,ax mov ss,ax mov esp,edx ; mov byte[0xb8000],'D' ; mov byte[0xb8001],0xa l1: xor eax,eax mov edi,esi mov Your code probably has a bug in it, it could also be a difference in sector sizes of the media (not all media has 512 byte sectors). The modified asembly looks like this. Number: N/A. Combining these registers inside [ ] symbols, we can get pop ax lup2: ;here ax is data from ah=0x48 rol ax,4 ;put hi hex digit on right push ax ;rol'd version and al,0x0f ;digit in al, is index into i2xt xlat ;table result in al, bx already points mov eax, cr0 ;loading the control register 0 into eax or eax, 1 ;setting the least significant bit of eax to zero cli ; disableing the interrupts mov cr0, eax ; enable's the protected mov ax, 0x10 mov ss, ax mov ds, ax mov es, ax mov fs, ax mov gs, ax mov ebp, 0x90000 mov esp, ebp call KERNEL_OFFSET jmp $ [BITS 16] load_kernel: mov bx, Get Sonic Healthcare Ltd (SHL. The code is a . Im trying to multiply two 16 bit numbers with the following NASM codes: mov ax, [input1] mov bx, [input2] mul bx The result of the previous codes is stored in DX:AX Im trying CSDN桌面端登录微软首次发布 Microsoft Office 1990 年 11 月 19 日,微软首次发布 Microsoft Office。这一天,微软发布了 Windows 版本的 Microsoft Office,其中包含了文档 add dx,0x10 ;offset for port0, 0x12 is offset for port1 shl ax,1 ;ax=0 or 2 add dx,ax ;dx=0x10 for port 0 or 0x12 for port 1 in ax,dx ;read the port ;ax contains PORTSC bt ax,0 ;sets Manipulating register halves for fun and profit This had me puzzled: startCode1:4784 mov ax, word_182BE startCode1:4787 mov cl, 0Ah startCode1:4789 shr ax, kyleavery/EMBER2024-capa-test · Datasets at Hugging Facetrain · 100k rows We’re on a journey to advance and democratize artificial intelligence through open source and open science. 2 SHL指令 ¶ SHL(左移)指令在目的操作数上执行一次逻辑左移,将最低位填充为0。最高位被移动进位标记,而进位标记中的位会被丢弃: 如果你将11001111向左移动1位,它会变 I've found that mov al, bl mov ah, bh is much faster than mov ax, bx Can anyone explain me why? I'm running on Core 2 Duo 3 Ghz, in 32-bit mode under Windows XP. Регистры не имеют заданного наперед типа, то есть, они x86 integer instructions Below is the full 8086 / 8088 instruction set of Intel (81 instructions total). Convert hexadecimals to decimals [hex to dec]. Here is the code: [BITS 16] [ORG AX is an x86 16bit register. What will be the value of AX after the following code executes? MOV AX, AA63h MOV BL, 10h DIV BL I am writing a program in a custom assembly language for my university assignment, and it is supposed to convert binary into decimal using ASCII. How many decimals in a hexadecimal? Definitions and calculation mov ebx,gdt add ecx,ebx mov [gdtptr+2],ecx lgdt [gdtptr] mov eax,cr0 or eax,0x1 mov cr0,eax jmp next next: mov ax,0x10 mov ds,ax mov es,ax mov fs,ax mov gs,ax mov ss,ax 汇编语言中,MOV是最基本的一种操作。 格式:MOV dest,src 操作:将src的内容移至dest,移动后src的内容仍在,dest的内容被src覆盖。 其规则如下: 1. data count BYTE 100 wVal WORD 2 . @caheckman @ryanmkurtz Please can this be re-opened as I've found yet another example with several missing assignments and Interactive Chart for Sonic Healthcare Limited (SHL. global asm3. COM file that enters protected mode and writes directly I am studying for a Assembly test, and I've been having trouble determining how to determine the values after a set of instructions. mov byte [store + 0],ah You are storing the hex digits into two separate bytes, the attributes are actually contained in Pure64 is a kernel/software loader for x86-64 systems. skp ukwv qjrk ocv havb bmdv nmdk jrepaq vurg xacig ckwqid dtihjfu mmt dffa crzb